(x^2+5)/(16x^2-25x^2+9)=0

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Solution for (x^2+5)/(16x^2-25x^2+9)=0 equation: 



(x^2+5)/(16x^2-25x^2+9)=0



Domain of the equation: (16x^2-25x^2+9)!=0

We move all terms containing x to the left, all other terms to the right

16x^2-25x^2!=-9

x∈R



We multiply all the terms by the denominator


(x^2+5)=0

We get rid of parentheses

x^2+5=0

a = 1; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·1·5
Δ = -20
Delta is less than zero, so there is no solution for the equation

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